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One-Dimensional Temperature Model, with advection, and column-integrated velocities

The temperature can be solved for in a simple 1-D column if we know the vertical () and horizontal () velocity distributions, as well as the horizontal temperature gradients (), and any internally generated heat terms (). In an equation of this from, the only neglected term is the horizontal heat transport due to horizontal conduction, and this is negligible.

The heat equation is just the following:

Expressing the total time derivative () in terms of a partial time derivative and the vertical and horizontal advection terms we obtain the following expression:

In solving this equation the z direction terms will be handled implicitly, while the x direction terms (horizontal velocity and temperature gradients) will be included with the internal heat generation term. These gradients will need to be derived from some external 1-D or 2-D grid in the horizontal direction.

Having obtained a solution for we can then obtain the ice hardness as a function of z from an expression of this form:

The strain rate is expressed in terms of a flow law, and is itself the vertical gradient of the horizontal velocity, given by the following expression:

The stress, , will be zero at the top surface and equal to the driving stress at the bed. Lacking any better models we will assume a linear distribution through the thickness, given by the following expression:

Hence we obtain the following expression:

which we can integrate from the bed (where the velocity is just equal to the sliding component of the velocity) to some depth, z, at which we wish to know the velocity. We will express the total horizontal velocity in terms of a parameter f, which is the fraction of the velocity due to sliding.

The sliding velocity can be expressed by some sliding relationship such as the one derived by Weertman [].

The horizontal velocity at any depth, z, will just be given by the following expression:

The integral can be evaluated numerically.

For a column-integrated model we will also need the column-averaged velocity, which is obtained by integrating the velocity from the bed to the surface and dividing by the thickness.

This also can be evaluated numerically.

For the temperature solution we also need the distribution of the vertical velocity in the z direction. This can be obtained from the incompressibility condition which requires that the sum of the principle strain rates be zero. Expressing the strain rates as velocity gradients we have the following expression:

or

In a flowband (1-D) model, the y term would be expressed in terms of the converging or diverging width of the flowband. In a map-plane (2-D) model, the horizontal velocity would have two components (x and y), each of which would be obtained from a treatment similar to the one above from which we obtained the x component of the velocity.

This can be solved for the gradient of the vertical velocity with respect to z and integrated from the bed to some depth z, obtaining the following expression:

Again, this integral can be evaluated numerically. We can probably assume that the vertical velocity at the bed is zero, in the absence of melting or freezing.

At this point we have both the vertical and horizontal velocities as a function of depth as required for the temperature solution. We can repeat the solution for this new distribution until the overall solution is self-consistent.



next up previous contents
Next: Flow law constant Up: Energy Conservation Previous: Semi-analytic steady state



James Fastook
Mon Feb 12 09:39:28 EST 1996